if 1.2 g can displace 1.12 g of hydrogen at stp, the equivalent weight of the metal is?
TheEdward:
2.2 g of what?
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1.2g of metal react with 1.12 liters at
1.2/1.12 g of metal react with 1 liter of H
(1.2 /1.12 ) x 22.4 of metal react with 22.4 liters at STP
24 g of metal reacts with 22.4 liter of H at STP or 1 g of H
so 1 mole of metal has 24 g
given mass of metal = 1.2 g
no of moles of metal = 1.2/24 = 0.05 moles
Equivalent weight = Molecular weight/Equivalents
Now calculate :
1.2/1.12 g of metal react with 1 liter of H
(1.2 /1.12 ) x 22.4 of metal react with 22.4 liters at STP
24 g of metal reacts with 22.4 liter of H at STP or 1 g of H
so 1 mole of metal has 24 g
given mass of metal = 1.2 g
no of moles of metal = 1.2/24 = 0.05 moles
Equivalent weight = Molecular weight/Equivalents
Now calculate :
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0
Answer:
12 gram
Explanation:
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