Math, asked by yugan3788, 1 year ago

If 1/2 is a root of equation x2+kx-5/4=0, then find the value of k

Answers

Answered by 15priyasingh
114
2 this is the answer of your queston
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Answered by sharonr
38

If 1/2 is root of equation x^{2}+k x-\left(\frac{5}{4}\right)=0 then value of k is 2

Solution:

Given that 1/2 is root of equation x^{2}+k x-\left(\frac{5}{4}\right)=0

We are asked to find the value of k

Since 1/2 is a root of given equation, it must satisfy the equation

Substitute x = 1/2 in given equation

\left(\frac{1}{2}\right)^{2}+\mathrm{k}\left(\frac{1}{2}\right)-\left(\frac{5}{4}\right)=0

On solving we get,

\left(\frac{1}{4}\right)+\mathrm{k}\left(\frac{1}{2}\right)-\left(\frac{5}{4}\right)=0

\frac{1+2 k-5}{4}=0

On simplification,

\begin{array}{l}{1+2 k-5=0} \\\\ {2 k-4=0} \\\\ {2 k=4} \\\\ {k=4 \div 2=2}\end{array}

Hence , the value of k is 2

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