Question

If 1/2 is a root of quadratic equation X^2+kx- 5/4=0 Find the value of K.​

Answer 1

Answer:

Given:

1/2 is one root of x*2+kx-5/4=0

To find:

the value of k

x*2+kx-5/4=0

(1/2)*2+k(1/2)-5/4=0

1/4+k(1/2)-5/4=0

k(1/2)+1/4-5/4=0

k(1/2)-4/4=0

k(1/2)-1=0

k(1/2)=1

k=1×2/1

k=2

Therefore the value of k is 2

Answer 2

Answer: Let p(x) = x² + Kx -5/4 = 0

And one of its zero is 1/2

P(x) = x²+ Kx - 5/4 = 0

P(1/2) = (1/2)² + k1/2 - 5/4 = 0

= 1/4 +k1/2 - 5/4

. =1+2k-5/4 = 0

. =2k -4/4 =0

. =2k - 4 = 0

. =2k = 4

. =K = 2