Question

if 1/2 is the zero of the polynomial p(x)=2x4-ax3+4x2+2x+1,find the value of a​

Answer 1

Answer:

$p(x) = {2x}^{4} - {ax}^{3} + {4x}^{2} + 2x + 1$

P(1/2)=2(1/2)^4 - a(1/2)^3 + 4(1/2)^2 + 2(1/2) + 1

=1/8-a/8+1+1+1

=

$\frac{1 - a + 8 + 8 + 8}{8}$

1-a+24=8

1-a=8-24

-a=-16-1

a=16

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