Question

If (1)(2010)+(2)(2009)+(3)(2008)+...+(2010)(1) = (335)(2011)a then the value of a must be​

Answer 1

Answer:

Given

(3+x2008+x2009)2010=a0+a1x+a2x2+....+anxn...(1)

Substituting x=ω in equation (1), we get,

(3+ω+ω2)2010=a0+a1ω+a2ω2+....

⇒22010=a0+a1ω2+a2ω+a3+a4ω+....(2)

Substituting x=ω2 in equation (1), we get,

22010=a0+a1ω2+a2ω+a3+a4

Answer 2

Hope it helps you........