Question

If 1.25 m sucrose solution has AT of 2.32°C,
what will be the expected value of AT, for
1.25m CaCl, solution?​

Answer 1

Answer:

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Explanation:

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Answer 2

ΔT = 6.96°C

Given:

1.25 m sucrose solution has ΔT of 2.32°C.

To find:

Expected value of ΔT, for 1.25m Ca$Cl_{2}$, solution.

Solution:

Sucrose is nonelectrolyte, therefore it has i = 1.

But for Ca$Cl_{2}$:

Ca$Cl_{2}$ → $Ca^{2+}$ + $2Cl^{-}$, the value of i = 3.

So,

ΔT = i x 2.32

=> 3 x 2.32

=> 6.96°C

Hence, ΔT = 6.96°C

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