If 1/3 *3 = 1 , but 1/3*3 = 0.33*3 = 0.99 , how is this possible if anyone solves this u are the most smartest
Answers
Answered by
1
The second way that is,
1/3*3=0.33*3=0.99
is wrong because by the rule of BODMAS we will solve the problem of 'OF', so when we solve the problem of 1/3*3 we first cancel the 3s then we will multiply the result with the remaining no. (i.e, 1) so the step would be
1/3*3=1/1*1=1.
so by the law of BODMAS we can only do this way, and not by the other way round.
if not known -
BODMAS = Bracket, Of, Division, Multiplication, Addition, Subtraction. This is a law which states the order in which the arithmetic operations should be done.
OF - multiplication of rational numbers with integers.
1/3*3=0.33*3=0.99
is wrong because by the rule of BODMAS we will solve the problem of 'OF', so when we solve the problem of 1/3*3 we first cancel the 3s then we will multiply the result with the remaining no. (i.e, 1) so the step would be
1/3*3=1/1*1=1.
so by the law of BODMAS we can only do this way, and not by the other way round.
if not known -
BODMAS = Bracket, Of, Division, Multiplication, Addition, Subtraction. This is a law which states the order in which the arithmetic operations should be done.
OF - multiplication of rational numbers with integers.
alistair2522:
Very good answer
Similar questions