Math, asked by shahzebkhan5454, 7 months ago

If 1/3 of a number exceeds its 2/7 by 1 , find the number.​

Answers

Answered by anjali10062007
1

Answer:

let the number =x

1/3 of a number = x/3

2/7 of the number = 2x/7

given

1/3 of a number exceeds its 2/7 by 1

x/3 - 2x/7 =1

do the lcm 

lcm = 3*7 =21

(7x-6x)/21 =1

⇒x/21 =1

∴ x= 21

required number = x =21

Answered by rajeevkumar12042000
1

Step-by-step explanation:

Let the number be X

x/3-2x/7=1

7x-6x/21=1

x/21=1

x=21

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