Question

If log a base3 + 6logb base 3 =2 , then express a in terms of b.​

Answer 1

Step-by-step explanation:

$log_{3}(a) + 6 log_{3}(b) = 2$

$log_{3}(a) + log_{3}( {b}^{6} ) = 2$

$log_{3}(a {b}^{6} ) = 2$

$a {b}^{6} = {3}^{2}$

$a {b}^{6} = 9$

$a = \frac{9}{ {b}^{6} }$