Question

if 1/3 of a number is 10 less than the original number then the no is

Answer 1

$\bf\huge{15}$

Let the number be x

According to the Question,

$=> \frac{1}{3} x = x - 10 \\\\ = > \frac{x}{3} + 10 = x \\\\ = > \frac{ x + 30}{3} = x \\\\ = > 3x = x + 30 \\\\ = > 2x = 30 \\\\ = > x = 15$


Hence, The number required is 15.

Answer 2

Answer:

Required number is 15.

Step-by-step explanation:

Here given,

$\frac{1}{3}$of a number is 10 less than the original number.

This is a problem of Algebra.

Let original number be x.

Now $\frac{1}{3}$of the number $= \frac{x}{3}$

According to question,

$x - \frac{x}{3} = 10$

We are Subtracting $\frac{x}{3}$from x,

$\frac{3x - x}{3} = 10$

$\frac{2x}{3} = 10$

By cross multiplication,

$2x = 10 \times 3 \\ 2x = 30 \\ x = \frac{30}{2} \\ x = 15$

Required number is 15.

Some extra important formulas of Algebra,

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)