if (1/5)3y=0.008, find the value of(0.25)y
kkn2:
is it 1/5×3y or (1/5)^3y
after or
Answers
Answered by
6
hola there,
Taking log on both sides we have
3y log(1/5) = log (0.008)
we can write
3y log(0.2) = log(0.2▪3) or 3 log(0.2)
3y log(0.2) =3 log(0.2)
solving we get y = 1
hence
0.25▪y = 0.25▪1 = 0.25
Taking log on both sides we have
3y log(1/5) = log (0.008)
we can write
3y log(0.2) = log(0.2▪3) or 3 log(0.2)
3y log(0.2) =3 log(0.2)
solving we get y = 1
hence
0.25▪y = 0.25▪1 = 0.25
bro but log(a×b) never equals b×log(a)
okk srry
yes correct
Answered by
9
3/5y=0.008
y=5/3×0.008
y=0.04/3
(0.25)y=1/4×y=1/4×0.04/3
=0.01/3
=0.003
y=5/3×0.008
y=0.04/3
(0.25)y=1/4×y=1/4×0.04/3
=0.01/3
=0.003
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