If 1/5 and -2 are respectively product and sum of the zeroes of a quadratic polynomial , find the polynomial
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Since it is a quadratic polynomial,
It is in the form of ax²+bx+c=0
Given sum of the roots = -2 which can be written as -(2)/1 = -b/a
Product of roots = 1/5 = c/a (constant /coefficient of x²)
Since, in product of roots a refers 5
we should change the sum of roots too to the denominator 5
Sum of roots = -2/1 which can also be written as -10/5 = -b/a
So from above information,
a = 5, b = 10, c = 1
Placing these values in ax²+bx+c = 0
We will get the quadratic equation
5x²+10x+1=0
It is in the form of ax²+bx+c=0
Given sum of the roots = -2 which can be written as -(2)/1 = -b/a
Product of roots = 1/5 = c/a (constant /coefficient of x²)
Since, in product of roots a refers 5
we should change the sum of roots too to the denominator 5
Sum of roots = -2/1 which can also be written as -10/5 = -b/a
So from above information,
a = 5, b = 10, c = 1
Placing these values in ax²+bx+c = 0
We will get the quadratic equation
5x²+10x+1=0
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