Question

If 1/6th of a wall is painted blue, 1/3rd is painted yellow and remaining 9m is painted white, what is the length of the wall​

Answer 1

Answer:

$\frac{1}{6} x + \frac{1}{3} x + 9$

$\frac{x}{6} + \frac{2x}{6} = - 9$

$\frac{3x}{6} = - 9$

$3x = - 54$

$x = \frac{ - 54}{3}$

$x = - 18$

Neglecting the negative as height cannot be negative

Length of the wall will be

$\frac{18}{6} + \frac{18}{3} + 9$

$3 + 6 + 9 = 18m$

Height of wall is 18m

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Answer 2

Length of wall will be 18 m

Step-by-step explanation:

Let the total length of the wall is x m

It is given that $\frac{1}{6}$ part of the wall is painted with blue color

So wall painted by blue color $=x\times \frac{1}{6}=\frac{x}{6}$

$\frac{1}{3}$ part is painted with yellow color

So wall painted by yellow color $=x\times \frac{1}{3}=\frac{x}{3}$

So length of wall painted by blue and yellow color $=\frac{x}{6}+\frac{x}{3}=\frac{9x}{18}=\frac{x}{2}$

So part of wall painted by white color $=x-\frac{x}{2}=\frac{x}{2}$

In question it is given that length of wall painted by white color is 9 m

So $\frac{x}{2}=9$

x = 18 m

So length of wall will be 18 m  

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