Question

If 1, 7, 13, 19 ..... are in AP. Then find the 10" term of AP.​

Answer 1

Given

AP: 1,7,13,19....

To find

$a _{10} = ?$

Solution:-

a = 1 , d = 6

Now, we all know (◍•ᴗ•◍)

$\sf a _{n} = a + (n - 1)d \\ \sf a _{10} = 1 + (10-1)6 \\\sf =1+9 \times 6 \\\bf =46 \\ \bf Therefore, \: the \: 10th \: term \: of \: AP \: is \: 46$

Answer 2

Answer:

Here let us consider

a=1 , d=7, n=10

where

l=a+(n-1) d

a10=1+ (10-1) 7

a10=1+ 9×7

a10=63 +1

a10=64

Therfore 10th term of the given AP is 64

Step-by-step explanation:

Hope it Will help you!!!