If 1 and -2 are two zeros of the polynomial (x³-4x²-7x+10), find it's third zero.
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Answered by
3
p(x) = x³ - 4x² - 7x + 10
On comparing,
a = 1 , b = -4 , c = -7 , d = 10
We know,
➜ Sum of zeroes = - b / a
Let the third zero be Ɣ
So,
☛ 1 + (-2) + Ɣ = -(-4)/1
☛ 1 - 2 + Ɣ = 4
☛ Ɣ = 4 + 1
☛ Ɣ = 5
Hence, the third zero is 5
Answered by
0
ATP
As -2 and 1 are it’s zeroes, it’s factors will (x+2) and (x-1)
Multiply x+2 and x-1 u will get x^2+x-2
Divide the above polynomial by x^2+x-2 u will get x-5
Therefore by equating it to zero u will x=5
As -2 and 1 are it’s zeroes, it’s factors will (x+2) and (x-1)
Multiply x+2 and x-1 u will get x^2+x-2
Divide the above polynomial by x^2+x-2 u will get x-5
Therefore by equating it to zero u will x=5
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