if 1 cubic metre of ice weights 900 kg, what is the weight of the cubical block of ice of side 50 cm.
Answers
Answered by
49
Density of ice = Mass / Volume
= 900 kg / (1 cm³)
= 900 kg/cm³
Mass of block = Volume of block × Density of ice
= (50 cm × 50 cm × 50 cm) × 900 kg/cm³
= 112 500 000 kilograms
= 112.5 × 10⁶ kg
Mass of cubical block is 112.5 × 10⁶ kg (= 112.5 gigagram)
= 900 kg / (1 cm³)
= 900 kg/cm³
Mass of block = Volume of block × Density of ice
= (50 cm × 50 cm × 50 cm) × 900 kg/cm³
= 112 500 000 kilograms
= 112.5 × 10⁶ kg
Mass of cubical block is 112.5 × 10⁶ kg (= 112.5 gigagram)
humzah1:
thank you junaid bai
You’re welcome :)
Answered by
13
Answer:
Answer is 112.5 kg
Step-by-step explanation:
Edge of cubical block of ice= 50 cm
volume of the ice block = 50×50×50=125000 cm^3
1 m^3 = 1000000 cm^3
volume = 125000/1000000=0.125 m^3
weight = 0.125×900=112.5 kg
Similar questions