Question

if 1 g of sulphur dioxide contains x molecules, how many molecules will be present in 1 g of oxygen????????????

Answer 1

1 mole of SO2 = 64g of SO2= 6.022×1023 molecules of SO2

1g of SO2= (6.022×1023)/64 = x molecules of SO2 (given) .......equation(i)

Now,

32g of O2=6.022×1023 molecules of O2

1g of O2=(6.022×1023)/32 molecules of O2

OR

=[(6.022×1023)/64]×2

= (x)*2 .....from equation(ii)

Hence 1g of O2 has = 2x molecules of O2