If (1+i/1-i)^2 = a+ib find (a,b)
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Step-by-step explanation:
(1+i/1-i)²=a+ib
1+2i-1/1-2i-1=a+ib
2i/-2i=a+ib
-1=a+ib
-1+i.0=a+ib
therefore, a=-1 ; b=0
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