Question

If '1' is a zero of p(x) = ax^2 - 3 (a-1) x -1 , then the value of 'a' is a) 1 b) 0 c) -1 d) 2

Answer 1

1

p(1)= a(1)^2-3a+3*1-1=0

a-3a+3-1=0

-2a+2=0

-2a=-2

a=-2/-2

therefore, a=1