Math, asked by abhidha411, 9 months ago


If 1 is a zero of polynomial p(a)= x² a ² -3xa +3x-1, find
the value of x

Answers

Answered by Anonymous
3

Answer:

Step-by-step explanation:

x^2 a^2-3x a +3x-1

if a = 1

x^2(1)^2-3x (1)+3x-1

x^2-3x+3x-1

x^2-1 = 0

x^2=1

x = √1

x = 1

Answered by belalrahman
0

Answers:

⇒p(a) = x^2 a^2 - 3xa +3x - 1

⇒p(1) = 2x * 2(1) - 3x(1) + 3x -1

⇒4x - 3x + 3x - 1 = 0

⇒4x = 1

⇒x = 1/4

ie. The value of x is 1/4.

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