Math, asked by riyagupta2656, 1 year ago

if 1 is a zero of polynomial p(x)= ax^2-3(a-1)x-1 find value of a

Answers

Answered by Anonymous
7
Hey friend here is your answer

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◆1 is zero so x=1

◆Equation- ax^2-3(a-1)x-1

◆Put x=1

◆a(1)^2-3(a-1)(1)-1=0

◆a-3a+3-1=0

◆-2a+2=0

◆-2a=-2

◆a=-2/-2

◆a=1

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⭐️Hope it helps you⭐️

✌️Rohan ( Maths aryabhatta)✌️
Answered by aman190k
7
Hey here is your answer
a=1
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