Question

if 1 is a zero of polynomial p(x)=ax2-3(a-1)then find the value of a​

Answer 1

Answer:

then p(1)=a *1* 2-3(a-1)

= 2a - 3a +3

= -1a +3

-3 = -1a

3 = a

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Answer 2

Answer:

a=0

Step-by-step explanation:

p(x)=ax²-3(a-1)

Given that 1is a zero of p(x)

So p(1)=0

=> a×1²-3(1-1)=0

=> a×1-3×0=0

=> a=0

Thus, the value of a is 0.(answer)

hope it will help you.