Question

plz solve this fast tomorrow is my exams ​

Answer 1

SOLUTION

Clearly,

=)angle ZYA= angle XYB= 90° (given)

=)angle ZYA + angle AYX= angle XYB+angle AYX

=) angle ZYX= angle AYB.......(1)

consider ∆AYB & ∆XYZ

AY= ZY (given)

BY= XY (given)

angleAYB= angleZYX [using (1)]

so, ∆AYB congurent ∆ZYX

=) AB= ZX hence, (c.p.c.t)

hope it helps ☺️