Question

The pressure exerted by a four legged table of weight 100 N is 40,000 pa. Calculate the area of each leg of the table at the point of contact with the floor

Answer 1

Pressure exerted by the four legged table = 40000 Pascals

Let the area of each leg be A.

Total area of four legged table = 4A

Weight of the table = 100 N

The pressure is defined as the force per unit area.

Hence, the formula for pressure is:

$Pressure = \frac{Force}{Area}$

Plugging the values:

$4 A = \frac{100}{40000}$

$A = \frac{1}{4 \times 400}$

A = 0.000625 m^2

Hence, the area of each leg is: 0.000625 m^2

Answer 2

Explanation:

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