Evaluate using identities:98×103
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Answered by
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(98)(103)
=(100-2)(100+3)
=using identity (x+a)(x+b)=(x)2+(a+b)x+ab
=(100-2)(100+3)=(100)2+(-2+3)(100)+(-2)(3)
=(100-2)(100+3)=10000+100-6
=(100-2)(100+3)=10094
Answered by
2
Answer:
S(98)(103)
=(100-2)(100+3)
=using identity (x+a)(x+b)=(x)2+(a+b)x+ab
=(100-2)(100+3)=(100)2+(-2+3)(100)+(-2)(3)
=(100-2)(100+3)=10000+100-6
=(100-2)(100+3)=10094tep-by-step explanation:
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