Question

If 1 is a zero of polynomial p(x) =ax2 -3(a-1)x-1 then find the value of a

Answer 1

Answer:

a=1

Step-by-step explanation:

Given,

p(x)=ax²-3(a-1)x-1

1 is zero of p(x).

so for x=1 p(x)=0.

p(x)=a(1)²-3(a-1)(1)-1=0

p(x)=a-3a+3-1=0

p(x)= -2a+2=0

-2a= -2

a= -2/-2

a=1.

Therefore the value of 'a' is '1'.

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