Question

If -1 is a zero of px=ax²-3(a-1)-1 then find the value of a

Answer 1

Answer:

a=1

Step-by-step explanation:

$P(x)=ax^{2} -3(a-1)-1\\\\-1 (Is..a..zero)\\\\therefore,\\\\putting,-1..in the eqution!\\----------------------------------\\\\so,\\a-3(a-1)-1=0\\=>a-3a+3-1=0\\=>-2a+2=0\\=>-2a=-2\\=>-2a=-2\\\\\\=>a=\frac{-2}{-2} \\=>a=1\\ans!\\thanks!!..$

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hope this will help you!

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thanks!