if 1 is a zero of the polynomial ax square - 3 (a - 1) x minus 1 then find the value of a
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ax²-3(a-1)x-1=0
a(1)²-3(a-1)(1)-1=0
a-3a+3-1=0
-2a-2=0
2a=-2
a=-2/2
a=-1
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vicky888agrawal:
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Answered by
2
x=1
f(x)= ax^2 -3(a-1)x -1
f(1)= a ×(1)- 3(a-1)1-1
= a -3a +3 -1
= -2a -2
= 2a +2 = 0
= 2(a +1)=0
= a +1 =0
= a = -1
hence, a = -1
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