If 1 is a zero of the polynomial ax squer -3(a-1)x-1 then find the value of a.
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a=-1
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Hi ,
It is given that 1 is the zero of the
polynomial p( x ) = ax² - 3(a - 1 )x - 1
p ( 1 ) = 0
a ( 1 )² - 3 ( a - 1 ) 1 - 1 = 0
a -3a + 3 - 1 = 0
- 2a + 2 = 0
-2a = -2
a = ( -2 ) /( - 2 )
a = 1
I hope this helps you.
:)
It is given that 1 is the zero of the
polynomial p( x ) = ax² - 3(a - 1 )x - 1
p ( 1 ) = 0
a ( 1 )² - 3 ( a - 1 ) 1 - 1 = 0
a -3a + 3 - 1 = 0
- 2a + 2 = 0
-2a = -2
a = ( -2 ) /( - 2 )
a = 1
I hope this helps you.
:)
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