Question

if 1 is a zero of the polynomial : f (x) = ax^3 - x^2 + x + 4 then find the value of 'a'​

Answer 1

Given :-

1 is zero of f(x) = ax³ - x² + x + 4

To Find :-

Value of a

Solution :-

By putting x = 1

f(1) = a(1)³ - (1)² + 1 + 4

0 = a(1) - 1 + 1 + 4

0 = 1a - 1 + 1 + 4

0 - a = -1 + 5

-a = 4

a = -4

Answer 2

Answer:

f(-1)= a(-1)³-(1)²+(-1)+4

=> -a-1-1+4=0

-a+2=0

2-0=a

a=2

Step-by-step explanation:

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