Question

if 1 is a zero of the polynomial kx2-3(k-1)x-1 then value of k is​

Answer 1

Answer:

p ( X ) = kx2 - 3( k - 1 ) x- 1

p( 1) = k(1)× 2-3( k-1)×(1)-1

0 = 2k -3k+3-1

0= -k+2

-k=-2

k= 2

Answer 2

The value of k = 1

Step-by-step explanation:

Given,

Let 1 is a zero of the polynomial P(x) = $kx^2-3(k-1)x-1$

To find, the value of k = ?

∴ P(1) = 0

⇒ P( 1) = k$(1)^2$- 3( k - 1)(1) - 1

⇒ k -3k+3 - 1  = 0

⇒  - 2k + 2  = 0

⇒ - 2k = - 2

⇒ k = 1

∴ The value of k = 1

Thus, the value of k is equal to 1.