Math, asked by jashminegupta1, 9 months ago

if 1 is a zero of the polynomial p(X) =ax^2-3(a-1) x-1 the find th value of a​

Answers

Answered by Anonymous
5

Step-by-step explanation:

p(x)=a×1-3-1

=a=1

Answered by Anonymous
4

Answer:

The value of a is 1

Step-by-step explanation:

Put X = 1

=> a(1)² - 3(a-1)1 - 1 = 0

=> a - 3a + 3 - 1 = 0

=> - 2a = - 2

=> a = 1

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