Math, asked by alwinrocks6363, 11 months ago

If 1 is a zero of the polynomial p(x) = ax² – 3(a – 1) x – 1, then find the value of a.

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Answered by kaushikumarpatel
5

Answer:

p(x) = ax² – 3(a – 1) x – 1

x = 1

0 = a (1)^2 - 3 (a - 1) 1 - 1

a - 3 a + 3 - 1 = 0

- 2 a = - 2

a = 1

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Answered by sparsh208
4

Answer:

your Answer is ready

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