For what value of k, – 4 is a zero of the polynomial x² – x – (2k + 2)?
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value of k = 11
Step-by-step explanation:
if we put value of p (x) = -4 p(x) = x^2 - x - (2k + 2) =0 ; p(-4) = (-4)^2 - (-4) -( 2k +2) =0. ; 16+4-2k+2=0 ; 22-2k =0 ; -2k = -22 ; k=-22/-2 ; k= 11
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