If α, β are the zeros of the polynomial 2y² + 7y + 5, write the value of α + β + αβ.
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7
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2y² + 7y + 5 = 0
Here a = 2 , b = 7 , c = 5
α,β are 2 zeroes
So sum of the zeroes = α + β = - b/ca= -7/2
Product of zeroes = αβ = c/a = 5/2
Now just put the values
α + β + αβ = ( α + β) + αβ
= -7/2 + 5/2
= -2/2 = -1
So required answer is -1
❤____________________
Answered by
2
2y² + 7y + 5 = 0
Here a = 2 , b = 7 , c = 5
α,β are 2 zeroes
So sum of the zeroes = α + β = - b/ca= -7/2
Product of zeroes = αβ = c/a = 5/2
Now just put the values
α + β + αβ = ( α + β) + αβ
= -7/2 + 5/2
= -2/2 = -1
So required answer is -1
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