Question

If -1 is a zero of the polynomial p(x) = ax3-x2+x+4 then value of 'a'

Answer 1

Answer:

Given that -1 is the zero,

So, x = -1

Putting the value of x,

ax³-x²+x+4

a(-1)³-(1)² +(-1)+4

-a -1 - 1 +4=0

a = 2

Answer 2

Answer:

$a=2$

Step-by-step explanation:

From the question,

Given,

-1 is the zero,

So,

x becomes equal to  -1

Putting the value of x, in $p(x) = ax^3-x^2+x+4$ the equation,

$p(x) = ax^3-x^2+x+4\\\\p(-1)=a(-1)^3-(1)^2 +(-1)+4\\\\p(-1)=-a -1 - 1 +4=0\\\\p(-1)=-a+2$

$p(-1)= 0\\\\-a+2=0\\\\a=2$

Hence, the value of $a$ is equal to 2.