Math, asked by Susmitaoram, 5 months ago

if 1 is a zeros of the the polynomial p(x)=ax^2-3(a-1)x-1 Then find the value of a​

Answers

Answered by Anonymous
0

Answer:

It is a polynomial.

Step-by-step explanation:

Answered by snehakamal013
4

Answer:

Given - p(x) = ax²-3(a-1) x-1

To fine - value of a solution,

Step-by-step explanation:

1 is a zero of polynomial,

= P(1) = 0

= P(1) = a(1)²- (3) (a-1) (1) -1

= a-3a + 3 - 1 = 0

= -2a + 2 = 0

= a= -2/-2 = 1

= a= 1 = Answer

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