Math, asked by pnkjsmddr, 11 months ago

the base of an isosceles traingle is 48 cm and one of its equal side is 84 cm find the area of the traingle​

Answers

Answered by iamastudent4444
0

Answer:

1931.96273cm²

Step-by-step explanation:

Using the formulas

A=bhb

2

hb=a2﹣b2

4

Solving forA

A=1

4b4a2﹣b2=1

4·48·4·842﹣482≈1931.96273cm²

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Answered by shreya7884
0

Answer:

Base=48

Equalside =84

Area of Triangle =1/2×base ×Height

1/2×48×84

=24×84

=2016cm²

Must be the answer

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