Question

If -1 is root of equation x2 + px +12=0, find the value of p.​

Answer 1

${x}^{2} + px + 12 = 0 \\ since \: - 1 \: is \: a \: root \: of \: the \: equation \: \\ { (- 1)}^{2} + p( - 1) + 12 = 0 \\ 1 - p + 12 = 0 \\ p = 13$

there you go :)

Answer 2

Answer: p = 13


Solution is in this picture!!!

I hope it will help you!!!☺️