Math, asked by manishsairama495, 1 year ago

If 1 is subtracted from the numerator and from the denominator of a fraction, the value obtained is 1/2. If 1 is added to its numerator and to its denominator, the resulting value is 2/3. Find the fraction.

Answers

Answered by Agastya0606
23

Given: If 1 is subtracted from the numerator and from the denominator of a fraction, the value obtained is 1/2. If 1 is added to its numerator and to its denominator, the resulting value is 2/3.

To find: Find the fraction.

Solution:

  • Let the fraction be x/y, then:
  • According to the first statement, we get:

                    x-1/y-1 = 1/2

  • Solving this, we get:

                    2(x-1) = y-1

                    2x - 2 = y - 1

                    2x - y - 1 = 0  .....................(i)

  • According to the second statement, we get:

                    x+1/y+1 = 2/3

  • Solving this, we get:

                    3(x+1) = 2(y+1)

                    3x + 3 = 2y + 2

                    3x - 2y + 1 = 0  .....................(ii)

  • Now solving: 2(i) - (ii), we get:

                     4x - 2y - 2 = 0

                    - 3x + 2y - 1 = 0

                      x - 3 = 0

                    x = 3

  • Putting x in (i), we get:

                    2(3) - y - 1 = 0

                    6 - y - 1 = 0

                    y = 5

                    x/y = 3/5

Answer:

                So the fraction is 3/5.

Answered by aonrizvi12345
1

Answer:

the fraction is 3/5

Step-by-step explanation:

Let the numerator of the fraction be x and its denominator be y,

i.e. let the fraction be x

y .

x

y

– 1

– 1 = 1

2 — (1)

+

+

x

y

1

1 = 2

3 — (2)

From (1),

2(x – 1) = y – 1

2x – 2 = y – 1

y = 2x – 1 — (3)

Substitute (3) into (2):

+

+

x

x

1

2 – 1 1 = 2

3

3(x + 1) = 4x

3x + 3 = 4x

x = 3

Substitute x = 3 into (3):

y = 2(3) – 1

= 5

The fraction is 3 /5

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