Question

if 1 is the 0 of polynomial p(x)= x sq-3(a-1)x-1 then find the value of a​

Answer 1

Answer:

a = 1

Step-by-step explanation:

Given a quadratic polynomial such that,

$p(x) = {x}^{2} - 3(a - 1)x - 1$

Also, it's given that,

1 is the zero of this polynomial.

To find the value of a.

We know that,

The zero of a polynomial satisfies the polynomial.

It means that, if we put the value of zero in that eqn , then it will be equal to 0.

Therefore, we will get,

=> p(1) = 0

=> (1×1) - 3(a-1)(1) - 1 = 0

=> 1 -3(a-1) - 1 = 0

=> -3(a-1) = 0

=> -3a + 3 = 0

=> 3a = 3

=> a = 3/3

=> a = 1

Hence, the required value of a = 1.