if -1 is the root of x²+ px² -x +2 then the value of p is?
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Answered by
1
Answer: p= -4
Step-by-step explanation:
q(-1)=0
(-1)^2 + p(-1)^2 - (-1) +2=0
1+p+1+2=0
p+4=0
p= -4!!!!!!!!!!!
Answered by
1
x = -1 ( given) root means value
So, x² + px² - x + 2 =0
• (-1)²+p(-1)²-(-1)+2 =0
• 1 + p + 1 + 2 =0
• 2 + 2 + p =0
• 4 + p =0
• p = -4
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