if 1 is the zero of p (x) =ax2 -3 (a-1)x-1 then find
Akshat14102004:
then find what bro?
Answers
Answered by
6
hi friend,
given, 1 is the zero of p(x)
→p(1)=0
→ax²-3(a-1)x-1=0
→a(1)²-3(a-1)-1=0
→a-3a+3-1=0
→2a=2
→a=1
I hope this will help u ;)
given, 1 is the zero of p(x)
→p(1)=0
→ax²-3(a-1)x-1=0
→a(1)²-3(a-1)-1=0
→a-3a+3-1=0
→2a=2
→a=1
I hope this will help u ;)
Answered by
3
ax^2-3ax+3x-1
put x=1
a (1)^2 -3a(1)+3(1)-1 =0
a-3a+3-1 =0
-2a+2 =0
-2a=0-2
-2a = -2
a = 2/2
a =1
put x=1
a (1)^2 -3a(1)+3(1)-1 =0
a-3a+3-1 =0
-2a+2 =0
-2a=0-2
-2a = -2
a = 2/2
a =1
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