if '1' is the zero of the equation ay^2+ay+3= 0 and y^2 + y + b = 0 then find the value of ab
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Hi ,
ay² + ay + 3 = 0 ----( 1 )
y² + y + b = 0 -------( 2 )
it is given that ' 1 ' is the zero of the equations
( 1 ) and ( 2 ) ,
substitute y = 1 in both the equations ,
a + a + 3 = 0
2a + 3 = 0
a = - 3/2 ----( 3 )
1 +1 + b = 0
2 + b = 0
b = - 2 ---( 4 )
Now ,
ab = ( -3/2 ) ( -2 ) [ from ( 3 ) and ( 4 ) ]
= 3
I hope this helps you.
:)
ay² + ay + 3 = 0 ----( 1 )
y² + y + b = 0 -------( 2 )
it is given that ' 1 ' is the zero of the equations
( 1 ) and ( 2 ) ,
substitute y = 1 in both the equations ,
a + a + 3 = 0
2a + 3 = 0
a = - 3/2 ----( 3 )
1 +1 + b = 0
2 + b = 0
b = - 2 ---( 4 )
Now ,
ab = ( -3/2 ) ( -2 ) [ from ( 3 ) and ( 4 ) ]
= 3
I hope this helps you.
:)
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