Question

If 1 is the Zero of the polynomial ax^2-3(a-1)x-1 then find the value of a

Answer 1

Given polynomial:
$a {x}^{2} - 3(a - 1)x - 1$

If 1 is a zero of this polynomial,
Therefore,

$a {(1)}^{2} - 3(a - 1)(1) - 1 = 0 \\ \\ {a} - 3a + 3 - 1 = 0 \\ \\ {a} - 3a + 2 = 0 \\ - 2a = - 2 \\ a = \frac{ - 2}{ - 2} = 1$
Therefore the value of a will be 1.