if 1 is the zero of the quadratic polynomial x2+kx+5. find the value of k
Answers
Answered by
28
Given that 1 is the root,
x = 1
Putting the value of x in the given equation,
x² + kx + 5 = 0
(1)² + k(1) + 5 = 0
1 + k + 5 = 0
6 + k = 0
k = -6
I hope this will help you
(-:
x = 1
Putting the value of x in the given equation,
x² + kx + 5 = 0
(1)² + k(1) + 5 = 0
1 + k + 5 = 0
6 + k = 0
k = -6
I hope this will help you
(-:
Answered by
8
Heya !!!
Given :- one zero of the given polynomial is 1.
It means 1 is a factor of the polynomial X²+KX+5.
(X-1) is also a factor of the given polynomial.
So,
(X-1) = 0
X = 1
P(X) = X²+KX+5
P(1) = (1)² + K × 1 + 5
=> 1 + K +5 = 0
=> K +6 = 0
=> K = -6
HOPE IT WILL HELP YOU...... :-)
Given :- one zero of the given polynomial is 1.
It means 1 is a factor of the polynomial X²+KX+5.
(X-1) is also a factor of the given polynomial.
So,
(X-1) = 0
X = 1
P(X) = X²+KX+5
P(1) = (1)² + K × 1 + 5
=> 1 + K +5 = 0
=> K +6 = 0
=> K = -6
HOPE IT WILL HELP YOU...... :-)
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