Question

if 1 is the zero value of polynomial
x2+kx-5 then find 'k'?​

Answer 1

1 is the zero value of x2+kx-5 then x=1

x2+kx-5=0

(1)^2+k-5=0

1+k-5=0

k-4=0

k=4

Answer 2

Answer:

k=4

Step-by-step explanation:

p(x) = x^2+kx-5

When x=1,

1^2+1k-5=0

1+k-5=0

k-4=0

k=4.

I hope this answer will help you.