if 1 is zeroes of polynomial p (x)=ax3-3(a-1)x-1 find value of a
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a=2.....................
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honeyaman4561:
a=2 kaisa aa
look
i think its correct
1-1=0 hoga
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p(1)= a(1)³ -3(a-1)x -1
p(1)=a-3a+3*1-1
p(1)=a -3a+2
p(1)= -2a+2=0
p(1)=-2a=-2
p(1)=2a=2
p(1)=a=2/2
p(1)=a=1
p(1)=a-3a+3*1-1
p(1)=a -3a+2
p(1)= -2a+2=0
p(1)=-2a=-2
p(1)=2a=2
p(1)=a=2/2
p(1)=a=1
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