Question

if 1 kg of water is mixed with 2 kg of liquid of density 3 g/cm3, then the average density of mixture will be :-
(a) 2.4 g/cm3
(b) 1.5 g/cm3
(c) 2 g/cm3
(d) 1.8 g/cm3

pls... Answer in detail by​

Answer 1

I think answer is d

D(density)=mass(m)/volume(v)

Density of solution is

=total mass/total volume

We know total mass of solution

=2000g+1000g=3000g

(weight in g becz d in g/cm3)

So

For water density in g/cm3 is 1

D=m/v--1=1000/v

v of water is 1000 cm3

For liquid of density in g/cm3 is 3

D=m/v---3=2000/v

v of liq. is 666.667

D of soln=total m/total v

D=3000(2000+1000)/1666.667(1000+666.67

D=approx 1.8

I hope it help