Question

If (1 - p) is a root of quadratic equation x^2 + px + (1 - p) = 0, then its roots are (a) 0, 1 (b) -1,1 (c) 0, -1 (d) -1, 2

Answer 1

c) 0,-1
Solve the eqn. by putting x=(1-p)
We get p=1
So root1=1-p=0
Using quadratic, sum of roots= -p=-1
So, root2=-1
So, 0 and -1